1. The problem statement, all variables and given/known data Given a rod of length 'l' placed upright on a smooth floor.A slight disturbance causes it to fall.Now required is the velocity with which the COM falls down when the rod makes angle θ with horizontal. 3. The attempt at a solution now let the middle portion of the rod be A,and the lower portion B.Using conservation of angular momentum,we get 0=(ml^2/12)ω-m*Va*l/2*cosθ By work energy theorem, mgl/2*(1-sinθ)=m(Va)^2/2+ml^2/12*ω^2 (ω about point B) What is the mistake I'm making here???