Which of the following is the right Procedure to get the minimum for f(x)?
Procedure 1: This is a closed interval, so we will have to calculate the value including and between [0,π/2].
To get critical points we do f'(x)=0. But here on f'(x) we get: -e-x-sin(x)=0, ie, there are no critical point and derivative exists everywhere? So we will calculate the points where derivatives will be 0. Exponential will never be zero, so consider sin, it will be zero only at point nπ/2.(here n=1)
Hence answer is π/2.
Procedure 2: If f'(x)<0, then it is minimum at that point. Here we are getting f'(x)<0 for [0,π/2] and inbetween points. So are we supposed to substitute each value in f(x) from options to check which gives the minimum?
Which Procedure is right?