I have a mixture methanol and water, at 25°C, and I want to take it to 250°C. I'll use two heat exchangers: one for taking the mixture from a liquid state (25°C) to a vapor state (X°C), and the second for taking it to the necessary temperature (250°C).
I know that methanol boiling temperature is 64 °C and water boiling temperature is 100°C, and it will be necessary to use two 'kinds' of heat, one for taking the component from 25°C to the boiling temperature, and another called the latent heat, for the phase change.
So, having methanol and water two different values of boiling temperature, what will be the value of X°C, approximately? 100°C, less or more?