1. The problem statement, all variables and given/known data Your friend is standing on the roof of his house, which is 11.5 meters off the ground. You are standing some distance away from the house and you kick a soccer ball at a total initial velocity of 18.0 m/s @ 60 degrees above the horizontal from ground level. If the soccer ball gets to the top of the house at the peak of its motion, how far away were you standing? 2. Relevant equations d=1/2g*t^2 d=vt 3. The attempt at a solution I already posted this once and got my mistake explained to me, so I tried again. First I found the time by doing d=1/2g*t^2 and got the time to be apporximately 1.52 seconds. Then I found the horizontal component, which would be 9 since the resultant and components form a 30-60-90 triangle. I multiplied 9 * 1.52 to get 13.68 meters, but my book says that this is wrong. Could anyone explain what I'm doing wrong and what I should change?