a) use v=u +at solve for a b) use v^2=u^2+2as solve for s. v is final vel; u is initial vel; t is time and a is accel. S is displacement; or distance in this case.
Hor vel= 300cos55 Mult this by 42s to get the horizontal (x) distance. (42s btw is a bit ridiculous, but hey ho)
c=f*lambda, or the speed of light =the frequency x the wavelength. Solve for wavelength, and remember to divide by 4 for a quarter.
Multiply EVERY term in the second bracket by -x; then do the same with the -1. Gather all the like terms together: all the exponents, then all the x terms and then all the numbers.
what is the value of 200 dimes? Subtract the answer from $28.10. How many quarters in your answer?
The ball's horizontal and vertical components are independent of each other. The 11m per sec makes no difference to your calculation. You know the starting vertical vel( 0m per sec); the time,(4.8sec) and the acceletation (g). Use v=u+at to get the velocity at 4.8 sec, the...
Drwls Could it also be solved by using v=u+at for the upward throw;then another motion equation for the upward distance; added to the fall time (sqrt 2h/g) all the way to the bottom? Charlie
I'm on the same problem and I'm having trouble solving it, can you go into a bit more detail.
Assuming air resistance is negligible.
What do you know? Initial velocity 5 m/s Time 6s Displacement (distance, not quite the same)60m Look at the standard motion equations, see if you can find one that uses all of these to give acceleration. Then use v=u+at.