In part (a) of this question suppose a stone is thrown verically upward with a speed of 12.9 m/s from the edge of a cliff and that h = 82 m. At what speed (in m/s) does the stone hit the ground?
T = v/g
Free fall equation
V = (V^2 - 2gvt . sin(feta) + (g^2) . (t^2))^0.5
The Attempt at a Solution
By using the first equation, I have worked out how long it takes to reach max. Then by using the answer for that, and using the known values, I have used the free fall equation to find out how long it takes to reach the bottom of the cliff. Then by using the last equation I ended up with 52.956 m/s as the answer.
I was told this was not the answer and was wondering what steps I am missing or completely doing wrong.
The question may sound silly but I guess what its trying to ask is 'what is the velocity of the stone right before it hits the ground?'.
Any help would be most appreciated.