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statement (ii) says that sqrt (x) and cubert (x) are even integers. only integers between 0 and 100 that satisfy to have sqrt and and cubert are 1 and and 64. we can not assume 1 as answer because it is not even integer. therefore, we are left with only 64, which satisfies both requirements.
if OA for this question is A, then what is OA for the following question (ETS 56), which is pretty much like the one, which we have been discussing :
if d is a positive integer, is sqrt(d)an integer?
(i) d is the squre of an integer.
(ii) sqrt(d) is the square of an integer.