Find the n’th Node from the end of a given Linked List
Objective: Given a linked list and integer ‘n’, write an algorithm to find the nth node from the end in the Linked List.
Original List : ->1->2->8->3->7->0->4 Output : 3rd Element from the end is : 7
Input: An unsorted linked list and integer k
Output: The kth to Last Element of a Singly Linked List
- Recurse through the Linked list
- When we reach to the end of the list, base case will return 0
- Now with each passing back call through stack, add 1 and return.
- When count hits k, print the value.
- Take two pointers approach
- Move first pointer by k
- now move both the pointers and when the first pointer reaches the end of the list the second pointer will be at the kth node from the end.
- Return the kth node data.
Original List : ->1->2->8->3->7->0->4 Recursion::3rd Element from the end is : 7 Iteration::5th Element from the end is : 8
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