posted by Anonymous .
A student throws a water balloon vertically downward from the top of a building.
The balloon leaves the thrower's hand with a speed of 6.00 m/s. Air resistance may be ignored,
so the water balloon is in free fall after it leaves the thrower's hand. (a) What is its speed after
falling for 2.00 s? (b) How far does it fall in 2.00 s?
(c) What is the magnitude of its velocity after falling 10.0 m?
(d) Sketch ay-t, vy-t, and y-t graphs for the motion.
The equations are (with distance Y and velocity V measured positive downward)
Y = 6t + 4.9 t^2
V = 6 + 9.8 t
Y=0 corresponds to the point at which it is dropped.
You do the graphing and plugging in of numbers, such as 2.00s for t in parts (a) and (b).
ay is 9.8 m/s^2 at all times it is falling