tanA = -2/6
a. Draw two possible locations on the coordinate axis for the terminal arm of angle A
b. Find two possible values for the measure of angle A and the related acute angle.
I have done the first part of the question what I need help with is the second part
This what I have done so far:
tanA = -2/6 = tanA = -0.3
A = tan^-1 = -0.3
A = -16.7
the -16.7 angle is related to the acute angle A
Therefore angle A = 180 - (-16.7)
Is this right? or Is there another way to do this?