Presentation on theme: "Chapter 3: DNA Replication"— Presentation transcript:
1 Chapter 3: DNA Replication Models of DNA replication: Meselson-Stahl ExperimentDNA synthesis and elongationDNA polymerasesOrigin and initiation of DNA replicationProkaryote/eukaryote models (circular/linear chromosomes)Telomere replication
2 Alternative models of DNA replication (Fig 3.1):
3 1958: Matthew Meselson & Frank Stahl’s Experiment Equilibrium density gradient centrifugation (Box 3.1)
4 1958: Matthew Meselson & Frank Stahl’s Experiment Semiconservative model of DNA replication (Fig. 3.2)
7 Discovered the mechanisms of DNA synthesis. 1955: Arthur KornbergWorked with E. coli.Discovered the mechanisms of DNA synthesis.Four components are required:dNTPs: dATP, dTTP, dGTP, dCTP(deoxyribonucleoside 5’-triphosphates)(sugar-base + 3 phosphates)2. DNA templateDNA polymerase (Kornberg enzyme)4. Mg 2+ (optimizes DNA polymerase activity)1959: Arthur Kornberg (Stanford University) & Severo Ochoa (NYU)
8 Three main features of the DNA synthesis reaction: DNA polymerase I catalyzes formation of phosphodiester bondbetween 3’-OH of the deoxyribose (on the last nucleotide) andthe 5’-phosphate of the dNTP.Energy for this reaction is derived from the release of two of the three phosphates of the dNTP.DNA polymerase “finds” the correct complementary dNTP at each step in the lengthening process.rate ≤ 800 dNTPs/secondlow error rate3. Direction of synthesis is 5’ to 3’DNA polymeraseImage credit:Protein Data Bank
11 There are many different types of DNA polymerase Polymerase Polymerization (5’-3’) Exonuclease (3’-5’) Exonuclease (5’-3’) #CopiesI Yes Yes YesII Yes Yes No ?III Yes Yes No3’ to 5’ exonuclease activity = ability to remove nucleotides from the3’ end of the chainImportant proofreading abilityWithout proofreading error rate (mutation rate) is 1 x 10-6With proofreading error rate is 1 x 10-9 (1000-fold decrease)5’ to 3’ exonuclease activity functions in DNA replication & repair.
12 Eukaryotic enzymes:Five common DNA polymerases from mammals.Polymerase (alpha): nuclear, DNA replication, no proofreadingPolymerase (beta): nuclear, DNA repair, no proofreadingPolymerase (gamma): mitochondria, DNA repl., proofreadingPolymerase (delta): nuclear, DNA replication, proofreadingPolymerase (epsilon): nuclear, DNA repair (?), proofreadingDifferent polymerases for the nucleus and mtDNASome polymerases proofread; others do not.Some polymerases used for replication; others for repair.Polymerases vary by species.
13 Origin of replication (e.g., the prokaryote example): Begins with double-helix denaturing into single-strands thus exposing the bases.Exposes a replication bubble from which replication proceeds in both directions.~245 bp in E. coli
14 Initiation of replication, major elements: Segments of single-stranded DNA are called template strands.Gyrase (a type of topoisomerase) relaxes the supercoiled DNA.Initiator proteins and DNA helicase binds to the DNA at the replication fork and untwist the DNA using energy derived from ATP (adenosine triphosphate).(Hydrolysis of ATP causes a shape change in DNA helicase)DNA primase next binds to helicase producing a complex called a primosome (primase is required for synthesis),Primase synthesizes a short RNA primer of nucleotides, to which DNA polymerase III adds nucleotides.Polymerase III adds nucleotides 5’ to 3’ on both strands beginning at the RNA primer.The RNA primer is removed and replaced with DNA by polymerase I, and the gap is sealed with DNA ligase.Single-stranded DNA-binding (SSB) proteins (>200) stabilize the single-stranded template DNA during the process.
16 DNA replication is continuous on the leading strand and semidiscontinuous on the lagging strand: Unwinding of any single DNA replication fork proceeds in one direction.The two DNA strands are of opposite polarity, and DNA polymerases only synthesize DNA 5’ to 3’.Solution: DNA is made in opposite directions on each template.Leading strand synthesized 5’ to 3’ in the direction of the replication fork movement.continuousrequires a single RNA primerLagging strand synthesized 5’ to 3’ in the opposite direction.semidiscontinuous (i.e., not continuous)requires many RNA primers , DNA is synthesized in short fragments.
17 Supercoiled DNA relaxed by gyrase & unwound by helicase + proteins: base pairs5’3’Supercoiled DNA relaxed by gyrase & unwound by helicase + proteins:SSB ProteinsPolymerase IIILagging strandOkazaki Fragments1Helicase+Initiator ProteinsATP23RNA primer replaced by polymerase I& gap is sealed by ligaseRNA PrimerprimasePolymerase III5’ 3’Leading strand
24 Concepts and terms to understand: Why are gyrase and helicase required?The difference between a template and a primer?The difference between primase and polymerase?What is a replication fork and how many are there?Why are single-stranded binding (SSB) proteins required?How does synthesis differ on leading strand and lagging strand?Which is continuous and semi-discontinuous?What are Okazaki fragments?
26 Replication of circular DNA in E. coli (3.10):Two replication forks result in a theta-like () structure.As strands separate, positive supercoils form elsewhere in the molecule.Topoisomerases relieve tensions in the supercoils, allowing the DNA to continue to separate.
27 Rolling circle model of DNA replication (3.11): Common in several bacteriophages including .Begins with a nick at the origin of replication.5’ end of the molecule is displaced and acts as primer for DNA synthesis.Can result in a DNA molecule many multiples of the genome length (and make multiple copies quickly).During viral assembly the DNA is cut into individual viral chromosomes.
28 DNA replication in eukaryotes: Copying each eukaryotic chromosome during the S phase of the cell cycle presents some challenges:Major checkpoints in the systemCells must be large enough, and the environment favorable.Cell will not enter the mitotic phase unless all the DNA has replicated.Chromosomes also must be attached to the mitotic spindle for mitosis to complete.Checkpoints in the system include proteins call cyclins and enzymes called cyclin-dependent kinases (Cdks).
29 Each eukaryotic chromosome is one linear DNA double helix Average ~108 base pairs longWith a replication rate of 2 kb/minute, replicating one human chromosome would require ~35 days.Solution ---> DNA replication initiates at many different sites simultaneously.Rates are cellspecific!Fig. 3.14
30 Fig. 3.13 - Replication forks visible in Drosophila
31 What about the ends (or telomeres) of linear chromosomes? DNA polymerase/ligase cannot fill gap at end of chromosome after RNA primer is removed. this gap is not filled, chromosomes would become shorter each round of replication!Solution:Eukaryotes have tandemly repeated sequences at the ends of their chromosomes.Telomerase (composed of protein and RNA complementary to the telomere repeat) binds to the terminal telomere repeat and catalyzes the addition of of new repeats.Compensates by lengthening the chromosome.Absence or mutation of telomerase activity results in chromosome shortening and limited cell division.
33 Final Step - Assembly into Nucleosomes: As DNA unwinds, nucleosomes must disassemble.Histones and the associated chromatin proteins must be duplicated by new protein synthesis.Newly replicated DNA is assembled into nucleosomes almost immediately.Histone chaperone proteins control the assembly.Fig. 3.17