1. The problem statement, all variables and given/known data Coasting along at 7.10 m/s, a 60.0 kg bicyclist on a 7.60 kg bicycle encounters a small hill. If the speed of the bicyclist is 6.00 m/s at the top of the hill, how much work was done on the bicyclist and her bike? 2. Relevant equations KEf-KEi=W .5mvi^2-.5mvf^2 kg*m^2*s^-2 m=60kg+7.60kg v=m/s 3. The attempt at a solution I tried finding the loss in KE and having that be the work done. I get .5mVf^2 -.5mVi^2 .5*67.6kg*36 - .5*67.6kg*50.41 I get -487 J and it tells me this is the wrong answer? What did I do wrong?